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2169dbf8ec40c284b009 · Strong equivalence of reversible circuits is coNP-complete

Strong equivalence of reversible circuits is coNP-complete

It is well-known that deciding equivalence of logic circuits is a coNP-complete problem. As a corollary, the problem of deciding weak equivalence of reversible circuits, i.e. ignoring the ancilla bits, is also coNP-complete. The complexity of deciding

Официальный источник · 2013-07-02

Полные импортированные сведения карточки
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  "title_en": "Strong equivalence of reversible circuits is coNP-complete",
  "designation": "",
  "series": "",
  "status": "",
  "date": "2013-07-02",
  "date_original": "July 2, 2013",
  "url": "https://www.nist.gov/publications/strong-equivalence-reversible-circuits-conp-complete",
  "source": "NIST Publications",
  "display_en": "",
  "authors_en": "Stephen P. Jordan",
  "abstract_excerpt_en": "It is well-known that deciding equivalence of logic circuits is a coNP-complete problem. As a corollary, the problem of deciding weak equivalence of reversible circuits, i.e. ignoring the ancilla bits, is also coNP-complete. The complexity of deciding",
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      "title_en": "Strong equivalence of reversible circuits is coNP-complete",
      "designation": "",
      "series": "",
      "status": "",
      "date": "2013-07-02",
      "date_original": "July 2, 2013",
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      "authors_en": "Stephen P. Jordan",
      "abstract_excerpt_en": "It is well-known that deciding equivalence of logic circuits is a coNP-complete problem. As a corollary, the problem of deciding weak equivalence of reversible circuits, i.e. ignoring the ancilla bits, is also coNP-complete. The complexity of deciding"
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